How do you find cos(2a+b) and tan(b/2)
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How do you find cos(2a+b) and tan(b/2)

[From: ] [author: ] [Date: 12-03-31] [Hit: ]
parentheses.tan(b/2) = csc(b) - cot(b)(This is a basic trigonometric identity.See Wikipedia if you dont trust my memory.I wont be offended.under something like half angle formulas........
Im asking how to go about solving questions like these..I know how to get alpha and beta just have only done (a+b), (a), or (b).

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Just as with cos(a+b), you have:

(1) (cos(2a) * cos(b)) - (sin(2a) * sin(b) <---- First critical step

Since: (2) cos(2a) = cos^2(a) - sin^2(a) and (3) sin(2a) = 2*sin(a)*sin(b) the answer is

([cos^2(a) - sin^2(a)] * cos(b)) - ([2sin(a)*sin(b)] * sin(b)) <----- Final Answer

where I have merely substituted (2) and (3) into (1) and hopefully kept balanced
parentheses.

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tan(b/2) = csc(b) - cot(b) (This is a basic trigonometric identity.)

See Wikipedia if you don't trust my memory. I won't be offended. It's probably
under something like "half angle formulas".

.
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keywords: tan,you,cos,How,and,do,find,How do you find cos(2a+b) and tan(b/2)
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