How do I find the points of inflection? (Calculus)
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How do I find the points of inflection? (Calculus)

[From: ] [author: ] [Date: 12-03-31] [Hit: ]
-Points of inflection are where the second derivative is equal to zero.Then we can see the only number we plug in the function and get 0 is zero.So the point of inflection is zero-To find the candidates for points of inflection, set the second derivative equal to zero.so, (0,......
f(x)=6x^3+2x+8

The answer I gave was 0,-1

What is the right answer and how do I get it?

Thank you for your help.

-
Points of inflection are where the second derivative is equal to zero.

F''(c) =0

So:

First derivative is:

f'(x)=18x^2 +2

The second derivative is:

f''(x)= 36x

Then we can see the only number we plug in the function and get 0 is zero.

So the point of inflection is zero

-
To find the candidates for points of inflection, set the second derivative equal to zero.

since f(x) = 6X³ + 2X + 8
f ‘(X) = 18X² + 2
f “(X) = 36X
0 = 36X
X = 0
f(0) = 6(0)³ + 2(0)+ 8 = 8
so, (0,8) is Point of Inflection
1
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