f(x)=6x^3+2x+8
The answer I gave was 0,-1
What is the right answer and how do I get it?
Thank you for your help.
The answer I gave was 0,-1
What is the right answer and how do I get it?
Thank you for your help.
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Points of inflection are where the second derivative is equal to zero.
F''(c) =0
So:
First derivative is:
f'(x)=18x^2 +2
The second derivative is:
f''(x)= 36x
Then we can see the only number we plug in the function and get 0 is zero.
So the point of inflection is zero
F''(c) =0
So:
First derivative is:
f'(x)=18x^2 +2
The second derivative is:
f''(x)= 36x
Then we can see the only number we plug in the function and get 0 is zero.
So the point of inflection is zero
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To find the candidates for points of inflection, set the second derivative equal to zero.
since f(x) = 6X³ + 2X + 8
f ‘(X) = 18X² + 2
f “(X) = 36X
0 = 36X
X = 0
f(0) = 6(0)³ + 2(0)+ 8 = 8
so, (0,8) is Point of Inflection
since f(x) = 6X³ + 2X + 8
f ‘(X) = 18X² + 2
f “(X) = 36X
0 = 36X
X = 0
f(0) = 6(0)³ + 2(0)+ 8 = 8
so, (0,8) is Point of Inflection