What is the pH of a buffer that consists of 0.301 M HF and 0.398 M KF? Ka of HF is 6.8 x 10-4
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What is the pH of a buffer that consists of 0.301 M HF and 0.398 M KF? Ka of HF is 6.8 x 10-4

[From: ] [author: ] [Date: 12-03-31] [Hit: ]
398 M KF? Ka of HF is 6.pH=-log(6.8E-4)+log(0.398/0.pH=3.......
What is the pH of a buffer that consists of 0.301 M HF and 0.398 M KF? Ka of HF is 6.8 x 10-4

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HF will be your acid in this solution and KF will be your base

using hasselbaches equation we can calculate for the pH

pH=pKa+log([base]/[acid])

pH=-log(6.8E-4)+log(0.398/0.301)
pH=3.289
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