One number is 6 less than a second number. twice the second number is 2 more than 3 times the first. find the

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One number is 6 less than a second number. twice the second number is 2 more than 3 times the first. find the

[From: ] [author: ] [Date: 12-02-22] [Hit: ]

........

Let f = first number and s = second number.
f = s - 6
2s = 3f + 2
solve the system of equations:
2s = 3(s - 6) + 2
2s = 3s - 16
-s = -16
s = 16
f = 16 - 6 = 10

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the number that is less than a second number is 8.
the second number is 14.
lolz my brain hurts from solving this now :P
i checked this like 150 times.... its right ;)

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x = y - 6
2y = 3x + 2

2y = 3(y-6) + 2
2y = 3y - 18 + 2
2y = 3y - 16
-y = -16
y = 16

x = 16 - 6
x = 10

1

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