Solve this geometry problem..

the length of one side of a square is 23.5 cm. find the length of a diagonal of a square


pls. give solutions

let ABCD be the square with BD as the diagnal.Now in triangle ABD angle A=90.using pythagoras th.BD^2=AB^2+AB^2
=2AB^2
BD=AB 2^1/2
BD=23.5 *2.414 (SINCE ROOT 2=2.414
=56.729

SINCE YOU SEEM TO BE QUITE YOUNG ,FOR YOUR CONVENIENCE
2^1/2=ROOT2(THERE IS NO SIGN OF ROOTS ON OUR KEYBOARDS)
HOPE YOU UNDERSTOOD

this is an incorrect reply

in a square, the diagonal is always equal to its side.* sqrt [2]

thus, since side = 23.5 cm,

so, diag.= sqrt [side^2+ side^2]

= sqrt [23.5^2+23.5^2]

= sqrt [1104.5]

= 33.234 cm

this is the correct answer and not 56.729

pl correct answer.

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The square has two equal sides and the diagonal is the hypotenuse.

sqrt(23.5^2*2)=33.2340 cm

Do 23.5^2 + 23.5^2 then square that which is 33.23

Make me you lazy asś