A piece of wire 12 in. long is bent to form a right triangle in which the shortest side is 2 in. Find the lengths of the other two sides.
Please show work (: Thanks!
Please show work (: Thanks!
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Let hypotenuse be H. We have
H^2 = (10-H)^2 + 2^2 or
H^2 - 4 = 100 +H^2 -20H or
20H = 104 or H = 5.2 in and other side is 4.8 in
H^2 = (10-H)^2 + 2^2 or
H^2 - 4 = 100 +H^2 -20H or
20H = 104 or H = 5.2 in and other side is 4.8 in
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let one side is x
and another side is 12-2-x = 10-x
using pythagoras theorem
(10-x)^2= x^2 + 2^2
100 - 20x = 4
x=24/5
anothe side 10-24/5
and another side is 12-2-x = 10-x
using pythagoras theorem
(10-x)^2= x^2 + 2^2
100 - 20x = 4
x=24/5
anothe side 10-24/5