Help on Quadratic functions
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Help on Quadratic functions

[From: ] [author: ] [Date: 12-02-12] [Hit: ]
the constant a can be found.Hence y= -3(x+1)(x-1).......
Determine the equation of a quadratic function that satisfies each set of conditions.
a) x-intercepts 1 and -1, y-intercept 3
Answers may vary but one example is y= -3(x+1)(x-1)

My question is why is the y-intercept at the beginning? And why is it negative?

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Start with y = a(x-1)(x+1) because if y = 0, then x = 1 or -1.
By setting x = 0, y = 3, the constant a can be found.
3 = a(0-1)(0+1)
3 = -a
a = -3
Hence y= -3(x+1)(x-1).
1
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