given the piecewise function
8-3x if x<4
10 if x=4
4/x-5 if x>4
a) find f(4)- Do I just plug in to where I see x=4?
b) compute limx-->4+ and limx-->4-
c) is f(x) continuous
8-3x if x<4
10 if x=4
4/x-5 if x>4
a) find f(4)- Do I just plug in to where I see x=4?
b) compute limx-->4+ and limx-->4-
c) is f(x) continuous
-
a) f(4) = 10, by definition of f.
b) lim(x→4+) f(x)
= lim(x→4+) 4/(x-5), since x > 4
= -4.
lim(x→4-) f(x)
= lim(x→4-) (8 - 3x), since x < 4
= -4.
c) By part b, lim(x→4) f(x) = -4.
However, since lim(x→4) f(x) ≠ f(4), f is not continuous at x = 4.
b) lim(x→4+) f(x)
= lim(x→4+) 4/(x-5), since x > 4
= -4.
lim(x→4-) f(x)
= lim(x→4-) (8 - 3x), since x < 4
= -4.
c) By part b, lim(x→4) f(x) = -4.
However, since lim(x→4) f(x) ≠ f(4), f is not continuous at x = 4.