How to solve integral of 1/(cos2y)^2 with respect to y

[From: ] [author: ] [Date: 12-02-11] [Hit: ]

∫sec^2(2y) dy

u = 2y

du/2 = dy

1/2*∫sec^2(u) du

1/2*tan(u) + C

1/2*tan(2y) + C

you do know what sec w means ?....{ (1/2) tan 2y }

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