How to solve volume/molarity problem? Chemistry help!

Q: What volume of 0.125 M oxalic acid, H2C2O4, is required to react with 35.2 mL of 0.546 M NaOH?

H2C2O4 (aq) + 2NaOH (aq)----------> Na2C2O4 (aq) + 2H2O (l)

I found the mols of oxalic acid, which is 0.0096096 mols oxalic acid based on balanced equation...but I'm not sure what to do next..

ratio of acid to base = 1:2
Moles of NaOH = M x L =0.546 x 0.035 = 0.0192 moles
Moles of acid required = 0./0192 / 2 = 0.00961
Voilume of acid required is L = moles / M = 0.00961 / 0.125 = 0.0769L = 76.9 ml.

Well, know that you know the moles of oxalic acid and the molar concentration (0.125M), plug it into the molarity formula and solve for the volume in L.

Molarity = moles/Volume (in L) -------> Volume = moles of oxalic acid/ Molar concentration

? mL H2C2O4 = 35.2 mL x 0.546 mmol NaOH x 1 mmol H2C2O4/2 mmol NaOH x 1 mL/0.125 mmol H2C2O4
= 76.9 mL H2C2O4