Help me solve roots of polynomial? (Algebra 2)

Let f(x) = 6x^4 + 19x^3 - 36x^2 - 49x + 60.

One root of f(x) is -5/3.

Find all four roots of f(x).

Hint: to find other roots, you may have to guess simple roots like x = 1, 2, 3 ...etc.

A. 4, 5/3, 1, 3/2
B. (4, 5/3, -1, -3/2
C. (-4, -5/3, 1, 3/2)
D. -4, -5/3, -1, -3/2

I don't understand how to find "roots" of polynomials. Can anyone help me on this? I only need help for this problem

f(x) = 6x^4 + 19x^3 - 36x^2 - 49x + 60.

f(x) = (3x+5)(2x^3 +3x^2 -17x +12)

f(x) = (3x+5)(2x-3)(x^2+3x-4)

f(x) = (3x+5)(2x-3)(x-1)(x+4)
Hence,
the roots are : 1, -4, 3/2, and, -5/3 >===========< ANSWER
aLSO,
THE ANSWER IS : C. (-4, -5/3, 1, 3/2) >======< ANSWER