Multiplying out these brackets? Please can u explain and help

[From: ] [author: ] [Date: 12-01-09] [Hit: ]

which is your answer.B) 5(3x - 2y)= (5 x 3x) + (5 x -2y)= 15x + (-10y)= 15x - 10yC) 2(4g² - 3g)= (2 x 4g²) + (2 x -3g)= (8g²) + (-6g)= 8g² - 6g-a) 6a + 21b) 15x - 10yc) 8g^2 - 6g.This is simple maths, you should really learn this stuff fast as the harder aspects of maths builds upon these foundations.......

*- refers to multiply

for c, the power (the indicey thingy) does not get multiplied with the constant, as u see from the above.
the number 2 multiplies with 4 rather than the power (^2)

hope it helps!
Cheers!

P.s i think this would be good to build up your foundation, like what Jack said.
http://www.cimt.plymouth.ac.uk/projects/…

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A) 3(2a + 7)
= (3 x 2a) + (3 x 7)
[Multiply each term inside the bracket with the term out side the bracket and add the product]
= (6a) + (21) = 6a + 21, which is your answer.

B) 5(3x - 2y)
= (5 x 3x) + (5 x -2y)
= 15x + (-10y)
= 15x - 10y

C) 2(4g² - 3g)
= (2 x 4g²) + (2 x -3g)
= (8g²) + (-6g)
= 8g² - 6g

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a) 6a + 21
b) 15x - 10y
c) 8g^2 - 6g.

This is simple maths, you should really learn this stuff fast as the harder aspects of maths builds upon these foundations.

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