write the equation that describes the function
http://i42.tinypic.com/vosdtz.jpg
http://i42.tinypic.com/vosdtz.jpg
-
f(x)=1/3x+1
-
the graph passes through points (-3,0) and (0,1)
the eqn of a straight line, in slope intercept form is:
y = mx + n, with m the slope and n the intercept
the intercept is the point where the graph intersects the y axis
in our case, its (0,1) => 1 = m*0 + n => n = 1
the def of the slope, knowing 2 points on the line, is :
m = (y2 - y1)/(x2 - x1), with (x1,y1) and (x2,y2) the coordinates of the 2 points
in our case, (x1 = -3, y1 = 0) and (x2 = 0, y2 = 1)
hence, m = (1 - 0)/(0 + 3) = 1/3
having found m and n, the eqn of the graph in slope-intercept form is:
y = 1/3 * x + 1
the eqn of a straight line, in slope intercept form is:
y = mx + n, with m the slope and n the intercept
the intercept is the point where the graph intersects the y axis
in our case, its (0,1) => 1 = m*0 + n => n = 1
the def of the slope, knowing 2 points on the line, is :
m = (y2 - y1)/(x2 - x1), with (x1,y1) and (x2,y2) the coordinates of the 2 points
in our case, (x1 = -3, y1 = 0) and (x2 = 0, y2 = 1)
hence, m = (1 - 0)/(0 + 3) = 1/3
having found m and n, the eqn of the graph in slope-intercept form is:
y = 1/3 * x + 1
-
sorry I am not able to go through your link
http://i42.tinypic.com/vosdtz.jpg
http://i42.tinypic.com/vosdtz.jpg