State the equation of the normal to the curve y=2x^2+5x at its minimum point
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State the equation of the normal to the curve y=2x^2+5x at its minimum point

[From: ] [author: ] [Date: 11-12-30] [Hit: ]
?So it will be y= a single value!! in this case you minimum y value which is y=-3.......
I found the minimum point of y=2x^2+5x to be (-1.25,-3.125) .. can you please tell me if that is correct and what would the equation of the normal to it be?
Would also help if you could talk me through it as i have an exam soon, thanks :)

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f ` (x) = 4x + 5 = 0 for turning point
x = - 5/4
f (-5/4) = 50/16 - 100/16 = - 50/16 = - 25/8

Minimum point (-5/4 , -25/8) <----------as you suggest

Equation of normal would be x = -5/4

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think about it !!

IF you have a minimum (or max) value..what is the gradient ??So it will be y= a single value!! in this case you minimum y value which is y=-3.125
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