I found the minimum point of y=2x^2+5x to be (-1.25,-3.125) .. can you please tell me if that is correct and what would the equation of the normal to it be?
Would also help if you could talk me through it as i have an exam soon, thanks :)
Would also help if you could talk me through it as i have an exam soon, thanks :)
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f ` (x) = 4x + 5 = 0 for turning point
x = - 5/4
f (-5/4) = 50/16 - 100/16 = - 50/16 = - 25/8
Minimum point (-5/4 , -25/8) <----------as you suggest
Equation of normal would be x = -5/4
x = - 5/4
f (-5/4) = 50/16 - 100/16 = - 50/16 = - 25/8
Minimum point (-5/4 , -25/8) <----------as you suggest
Equation of normal would be x = -5/4
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think about it !!
IF you have a minimum (or max) value..what is the gradient ??So it will be y= a single value!! in this case you minimum y value which is y=-3.125
IF you have a minimum (or max) value..what is the gradient ??So it will be y= a single value!! in this case you minimum y value which is y=-3.125