First, factor 2340
2340 =>
234 * 10 =>
2 * 117 * 2 * 5 =>
2 * 9 * 13 * 2 * 5 =>
2^2 * 3^2 * 5 * 13
A perfect square is made up of factors like this:
a^2 * b^2 * c^2 * d^2 * ....
So, in order to get that, we need another 5 and 13
5 * 13 = 65
65 is the answer.
2340 =>
234 * 10 =>
2 * 117 * 2 * 5 =>
2 * 9 * 13 * 2 * 5 =>
2^2 * 3^2 * 5 * 13
A perfect square is made up of factors like this:
a^2 * b^2 * c^2 * d^2 * ....
So, in order to get that, we need another 5 and 13
5 * 13 = 65
65 is the answer.
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The prime factorization of 2340 is:
2340 = 2 2 3 3 5 13
If we want the product of this and some other number to be a perfect square, then the product must contain an even number of each prime factor. The smallest such number is therefore:
5 x 13 = 65
And 65 x 2340 = 390 = 2 3 5 13
2340 = 2 2 3 3 5 13
If we want the product of this and some other number to be a perfect square, then the product must contain an even number of each prime factor. The smallest such number is therefore:
5 x 13 = 65
And 65 x 2340 = 390 = 2 3 5 13
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Trying division by 1, 4, 9, 16, 25, 36, etc as follows :
2340 / 4 = 585
585 / 9 = 65
Multiply 2340 by 65 to make it a perfect Square number. ANSWER
2340 / 4 = 585
585 / 9 = 65
Multiply 2340 by 65 to make it a perfect Square number. ANSWER
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factor 2340=4*585=4*5*117=4*3*5*39=4*9*5*13=2^2…
So multiply by 5*13 (so every prime is to an even power!)
So multiply by 5*13 (so every prime is to an even power!)
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prime 2340
u l need 65 to make it perfect square
u l need 65 to make it perfect square