Given f(x) = 1-3x and g(x) = x+2, find (f^-1 - g^-1) (1). How do you solve it?
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James -
I'm going to assume that f^-1 means the "inverse" of f:
The argument is 1, so to find the inverse all you really need to find is what value of x will result in f(x) or g(x) to equal 1:
f(x) = 1-3x
1 = 1 - 3x, so x = 0
g(x) = x+2
1 = x + 2, so x = -1
Finally, simply plug these numbers into the formula:
(f^-1 - g^-1) (1) = 0 - (-1) = 1
Answer is 1
Hope that helps
I'm going to assume that f^-1 means the "inverse" of f:
The argument is 1, so to find the inverse all you really need to find is what value of x will result in f(x) or g(x) to equal 1:
f(x) = 1-3x
1 = 1 - 3x, so x = 0
g(x) = x+2
1 = x + 2, so x = -1
Finally, simply plug these numbers into the formula:
(f^-1 - g^-1) (1) = 0 - (-1) = 1
Answer is 1
Hope that helps