so tomorrow i have an important math final and i am still confused with how to do these probelms.
I would very much appreciate an explanation ... thank-you so much !!
I am very confused with graphing :(
53. Y = x -5
54. -x + 4y = -12
I would very much appreciate an explanation ... thank-you so much !!
I am very confused with graphing :(
53. Y = x -5
54. -x + 4y = -12
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Y=mx+b m is the slope and b is the y intercept
so for 53. the y intercept is at -5 and the slope is 1 so up 1 over 1
54. get y by itself, y=1/4x-3
the y intercept is at -3 and the slope is 1/4 so up 1 over 4 (Rise/Run)
so for 53. the y intercept is at -5 and the slope is 1 so up 1 over 1
54. get y by itself, y=1/4x-3
the y intercept is at -3 and the slope is 1/4 so up 1 over 4 (Rise/Run)
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Matt's answers are correct
It is easiest to put in slope intercept form y=mx+b
To graph it, you can substitute numbers and plot the point
y= x - 5
When x=0, y=-5 so that's a point at (0,-5)
Plot a second point
When x = 5, y=0 so that's at (5,0)
Draw a line through these two points and that's the graph. You can choose any two points.
It will have a slope of 1 and y-intercept at -5 which you also see from the equation of the line y=1x-5
54. -x + 4y = -12
y=mx+b
4y=x-12
y=1/4x-3
You can look at the equation and see it crosses the y-axes (y-intercept) at -3. This occurs when x = 0.
You can either count up 1 and over 4 to get a point or substitute any number for the x value and calculate the y value.
At x=4, y =1/4 (4)-3 = -2 so (4,-2) is a point on the line.
Hope this helps.
It is easiest to put in slope intercept form y=mx+b
To graph it, you can substitute numbers and plot the point
y= x - 5
When x=0, y=-5 so that's a point at (0,-5)
Plot a second point
When x = 5, y=0 so that's at (5,0)
Draw a line through these two points and that's the graph. You can choose any two points.
It will have a slope of 1 and y-intercept at -5 which you also see from the equation of the line y=1x-5
54. -x + 4y = -12
y=mx+b
4y=x-12
y=1/4x-3
You can look at the equation and see it crosses the y-axes (y-intercept) at -3. This occurs when x = 0.
You can either count up 1 and over 4 to get a point or substitute any number for the x value and calculate the y value.
At x=4, y =1/4 (4)-3 = -2 so (4,-2) is a point on the line.
Hope this helps.
-
So you're trying to graph the equations? If so...
Form: mx+b, where m is slope and b is y-intercept
53. y = x - 5. Since the number being multiplied by x is 1, the slope is 1. The y-intercept is -5. Therefore. Put a dot on (0, -5). Then, move up 1 and right 1 (slope is rise over run), to (1, -4). Keep doing this and connect the points with a line. You're good now.
54. Put in slope-intercept form.
-x+4y = -12
-x+4y+12 = 0
-4y = 12 - x
y = -3 + (1/4)x
Form: mx+b, where m is slope and b is y-intercept
53. y = x - 5. Since the number being multiplied by x is 1, the slope is 1. The y-intercept is -5. Therefore. Put a dot on (0, -5). Then, move up 1 and right 1 (slope is rise over run), to (1, -4). Keep doing this and connect the points with a line. You're good now.
54. Put in slope-intercept form.
-x+4y = -12
-x+4y+12 = 0
-4y = 12 - x
y = -3 + (1/4)x
12
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