One more calculus problem! very simple!
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One more calculus problem! very simple!

[From: ] [author: ] [Date: 11-12-09] [Hit: ]
Any help owuld be appreciated! Thanks so much!-d/dx sin(x) at pi is equal to that hard to work out limit. So you substitute!......
I know this is just conceptual, I just am confused with the question...
lim as h -> 0 of the function [sin(pi+h)-sinpi]/h = ?

it is just the definition of a derivative, but I am confused with what the problem is asking?
Any help owuld be appreciated! Thanks so much!

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d/dx sin(x) at pi is equal to that hard to work out limit. So you substitute! It simplifies to cos(pi) which is just -1
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