lim as x -> infinity (5x^(3/2))/(4x^2 + 1)
Help?
Help?
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Divide top and bottom by x^2:
lim as x -> infinity (5x^(3/2))/(4x^2 + 1)
= lim as x -> infinity (5x^(3/2)/x^2)/(4 + 1/x^2)
= lim as x -> infinity (5x^(-1/2))/(4 + 1/x^2)
= lim as x -> infinity (5/x^(1/2))/(4 + 1/x^2)
= 0/(4 + 0)
= 0
Lord bless you today!
lim as x -> infinity (5x^(3/2))/(4x^2 + 1)
= lim as x -> infinity (5x^(3/2)/x^2)/(4 + 1/x^2)
= lim as x -> infinity (5x^(-1/2))/(4 + 1/x^2)
= lim as x -> infinity (5/x^(1/2))/(4 + 1/x^2)
= 0/(4 + 0)
= 0
Lord bless you today!