Please explain how to solve for A, B, and C
I don't get anything about it
(2,6)
I don't get it!
And i can't use y = Mx + B or Y - Y1 = M(x - x1)
You replace which numbers? Then what? How do you get each? I want not just the answer, but how to get it, because I don't want to have to ask for EVERY question. Thanks!
I don't get anything about it
(2,6)
I don't get it!
And i can't use y = Mx + B or Y - Y1 = M(x - x1)
You replace which numbers? Then what? How do you get each? I want not just the answer, but how to get it, because I don't want to have to ask for EVERY question. Thanks!
-
The (2,6) is an ordered pair which gives you the x coordinate and y coordinate. The standard formula for an ordered pair is (x,y). So, your x is 2, here, and your y is 6. Just plug those numbers into your equation and you get: A(2) + B(6) = C. Since that looks a little weird, we usually write it as 2A+6B= C. So now, your C is already given to you in this equation. The equation that we just wrote is solving for your "C." To solve for A, you would subtract both sides by "6B", so you get the equation: 2A=C-6B. Now divide both sides by "2" and you get A= (C-6B)/2 or A= (C/2)- 3B. You can do the same thing for "B." Start with your equation 2A+6B=C and subtract both sides by "2A." You now have 6B = C - 2A. Now, to isolate the "B," you divide both sides by "6." So, you get the equation B= (C-2A)/6. You can also write this as B= (C/6)-(1/3)A. Theoretically, you can plug in any value for "A," "B," or "C" and come up with the value of whichever variable you are missing.