What is the peroid of y= - 2sec πx/2

I know the the period should be found form 2π/B & B is any number beside X so here the period should be 4π or 4?

y= tan x/2
Period = 4pi is correct or not?

I am confused could you please help? Thanks.

The problem is weirdly written. I'm guessing you mean y = -2sec (π/2)x (Which is the same thing as the equation above)

You divide 2π by B which is π/2

So you do 2π times 2/π (Since that's the reciprocal of π/2)

As a result you get a period of 4.

Also, the period of y = tan x/2 (or tan(1/2)x) is 2π, because the period for the tangent is π/b, not 2π/b like it is for sin/cos/sec/csc

The period should be 4. Usually, the period of a secant function is 2π. Inside the secant funtion, x is already being multiplied by π, so that would make the period 2. However, x is also being divided by 2, meaning the period will be twice as long, making it 4. Hope this helps.