namely -3 and -4so we have (x-3)(x-4)-You need to find 2 numbers that multiply to 12 and add to -7...you would have -3 and -4then you would have(x-3)(x-4)That would be the factored version.......
The factors of 12 are
1,12
2,6
3,4
as the only set of factors which when multiplied together equal 12 and when multiplied individually by 1 and added together make 7 are 3 and 4
(x+3) and (x+4)
however, our middle term must be negative otherwise our re-multiplied
trinomial is the wrong on the middle term i.e. x^2+7x+12
changing both plus signs to minus signs corrects the middle term without changing the last terms positive status
so
(x-3)(x-4) = x^2-7x+12
you need to find two numbers that multiply together to produce 12 and that add together to make -7, namely -3 and -4
so we have (x-3)(x-4)
You need to find 2 numbers that multiply to 12 and add to -7...
you would have -3 and -4
then you would have
(x-3)(x-4)
That would be the factored version.
