I need 5 cone with different dimensions with a volume of 100 pi please

I need the radius and height of the cone that make the volume 100 pi (314.15 cm3)
Thank you xx

V = (1/3)*pi*r^2*h
(1/3)*pi*r^2*h = 100*pi
(1/3)*r^2*h = 100
r^2 * h = 100 / (1/3)
r^2 * h = 100 * 3
r^2 * h = 300

Using positive integers only, these are the only possible solutions:
r = 10, h = 3
r = 5, h = 12
r = 2, h = 75
r = 1, h = 300
If you allow non-integers, there are infinity solutions, e.g.:
r = 4, h = 18.75

The volume of a right circular cone (one where the point of the cone is directly over the center of the circle at the base of the cone) is given by

V = π * R^2 * H / 3

where R is the radius of the circle at the base, and H is the height. See below for a derivation if you're interested.

So, set V = 100 π cm^3, and you get

V = π * R^2 * H / 3
100 π cm^3 = π * R^2 * H / 3
100 cm^3 = R^2 * H / 3
300 cm^3 = R^2 * H
H = 300 cm^3 / R^2

So, pick 5 values of R, and solve for H. Let's pick R = 10 cm. Then

H = 300 cm^3 / (10 cm)^2
H = 300 cm^3 / (10^2 cm^2)
H = 300 cm^3 / (100 cm^2)
H = 3 cm

Feel free to pick other values! I hope that helps!

Derivation: If you don't know calculus, skip this section. A right circular cone is the solid of revolution of a right triangle.

..|\
..|..\
..|....\
H|......\
..|_____\
......R

If I take a horizontal slice through the triangle at height y (with y = 0 at the base, and y = H at the top), it has a width w(y) = R*(1 - y / H). When that slice is revolved, it forms a circle with radius w(y), and thus has area pi * [w(y)]^2.

.....|\
.....|..\
H...|.....\
.....|-w(y)-\
...y|______\
........R

The cone volume is then the integral of these areas over the height,

V = ∫π [R(1 - y/H)]^2 dy
V = π ∫ R^2(1 - y/H)^2 dy
V = π R^2 ∫ (1 - 2y/H + y^2/H^2) dy
V = π R^2 [ y - y^2/H + y^3/(3H^2) ] from y = 0 to y = H
V = π R^2 { H - H^2/H + H^3/(3H^2) - [0 - 0^2/H + 0^3/(3H^2)] }
V = π R^2 { H - H^2/H + H^3/(3H^2) - 0 }
V = π R^2 { H - H + H/3 }
V = π R^2 { H/3 }
V = π R^2 H / 3