Arrange the function (1.5)^n, n^100, (log n)^3, sqrt(n)*logn, 10^n, (n!)^2, and n^99+n^98 in a list so that...
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > Arrange the function (1.5)^n, n^100, (log n)^3, sqrt(n)*logn, 10^n, (n!)^2, and n^99+n^98 in a list so that...

Arrange the function (1.5)^n, n^100, (log n)^3, sqrt(n)*logn, 10^n, (n!)^2, and n^99+n^98 in a list so that...

[From: ] [author: ] [Date: 11-10-14] [Hit: ]
Note: sqrt(n) log n is O(n^(1/2 + d)) for any d > 0.Thats why its ordered ahead of (log n)^3, which is O(n^d) for any d > 0,I hope this helps!......
Arrange the function (1.5)^n, n^100, (log n)^3, sqrt(n)*logn, 10^n, (n!)^2, and n^99+n^98 in a list so that each function is big-O of the next function.

Stuck on this problem for my discrete math class. Any help is greatly appreciated.

-
Idea: logarithms < power functions (of increasing degree) < exponential functions < factorials.

(log n)^3, sqrt(n) log n, n^99 + n^98, n^100, (1.5)^n, 10^n, (n!)^2

Note: sqrt(n) log n is O(n^(1/2 + d)) for any d > 0.
That's why it's ordered ahead of (log n)^3, which is O(n^d) for any d > 0, like d < 1/2.

I hope this helps!
1
keywords: and,100,1.5,list,98,sqrt,that,logn,function,99,in,10,log,so,Arrange,the,Arrange the function (1.5)^n, n^100, (log n)^3, sqrt(n)*logn, 10^n, (n!)^2, and n^99+n^98 in a list so that...
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .