I don't understand how to do the math for this. This is not for school, but
rather for my own person curiosity. If the math could be explained, and a
method for solving this problem given, that would be wonderful. However,
if it is too complicated to post as an answer, I would understand.
However, I'd also like to know this.
100 miles per second, how long to travel 10ft, 100ft, 1000ft.
As well as.
3000 miles per second, how long to travel 10ft, 100ft, 1000ft.
Thank you very much!
rather for my own person curiosity. If the math could be explained, and a
method for solving this problem given, that would be wonderful. However,
if it is too complicated to post as an answer, I would understand.
However, I'd also like to know this.
100 miles per second, how long to travel 10ft, 100ft, 1000ft.
As well as.
3000 miles per second, how long to travel 10ft, 100ft, 1000ft.
Thank you very much!
-
we have:
time = distance/velocity
however, you have two distance units, so you need to convert the feet into miles.
to do this, we have 5280 ft in each mile. therefore 20 feet = 20ft/5280 ft per mile = 0.0037878 miles
Plug into the formula above:
time = 0.0037878 miles/ 100 miles per second
time = 3.78 *10^-5 seconds. or 37.8 micro seconds
Do the same for all other distances and velocities. hope this helps!
time = distance/velocity
however, you have two distance units, so you need to convert the feet into miles.
to do this, we have 5280 ft in each mile. therefore 20 feet = 20ft/5280 ft per mile = 0.0037878 miles
Plug into the formula above:
time = 0.0037878 miles/ 100 miles per second
time = 3.78 *10^-5 seconds. or 37.8 micro seconds
Do the same for all other distances and velocities. hope this helps!
-
Convert the number of feet in 100 miles, and that's the number of feet you travel in 1 second. Divide that number into the number of feet you are traveling, and you'll know how long it takes to go that far.
Since there are 5280 feet in 1 mile, there are 528000 feet in 100 miles. At 100 miles per second, you would be going 528000 feet per second.
At that speed, to go 20 feet it would take 20/528000 ≈ .0000379 seconds
For your other distances, divide the number of feet by 528000
Use the same method to determine the times for 3000 miles per second (Hint, since it's 30 times as fast, it takes 1/30 the time it would take at 100 miles per second)
Since there are 5280 feet in 1 mile, there are 528000 feet in 100 miles. At 100 miles per second, you would be going 528000 feet per second.
At that speed, to go 20 feet it would take 20/528000 ≈ .0000379 seconds
For your other distances, divide the number of feet by 528000
Use the same method to determine the times for 3000 miles per second (Hint, since it's 30 times as fast, it takes 1/30 the time it would take at 100 miles per second)
-
First you have to change the units. Miles to feet. Therefore 100mi/sec is 528000ft/sec
Make a proportion.
528000 ft . `20 ft
--------------- = ----------
1 sec . .x
Then you cross mulitply: 528000x = 20ft/sec
Solve for x and there you go!
For the others, just substitute the other numbers for the numbers in the proportion (if you know what I mean...)
Make a proportion.
528000 ft . `20 ft
--------------- = ----------
1 sec . .x
Then you cross mulitply: 528000x = 20ft/sec
Solve for x and there you go!
For the others, just substitute the other numbers for the numbers in the proportion (if you know what I mean...)
-
(100miles/1second)(5280feet/1mile)=528,0…
You are traveling at a rate of 528,000 feet per second. Set up a proportion. And cross-multiply to solve.
528,000feet/1second = 20feet/xseconds
528,000/1=20/x
528,000x=20(1)
528,000x=20
x=20/528,000
x=(2x10^1)/(5.28x10^5)
x=0.4x10^(-4)
x=0.00004
It would take approximately 0.00004 seconds.
You are traveling at a rate of 528,000 feet per second. Set up a proportion. And cross-multiply to solve.
528,000feet/1second = 20feet/xseconds
528,000/1=20/x
528,000x=20(1)
528,000x=20
x=20/528,000
x=(2x10^1)/(5.28x10^5)
x=0.4x10^(-4)
x=0.00004
It would take approximately 0.00004 seconds.
-
I am gusing 2seconds