I need help simplify this equation...
(2x^(2) -3x+1)(4)(3x+2)^(3) + (3x+2)^(4)(4x-3)
Im trying to understand how to do these problems but i don't even know where to get started...please show steps
(2x^(2) -3x+1)(4)(3x+2)^(3) + (3x+2)^(4)(4x-3)
Im trying to understand how to do these problems but i don't even know where to get started...please show steps
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Based on your question description I get
(20x^2 - 13x - 2) (3x+2)^3
This is found by taking the second term in your question (3x+2)^4(4x-3) and rewriting it as
(3x+2)^3(4x-3)(3x+2) then expanding (4x-3)(3x+2) to get 12x^2 -x - 6
giving (12x^2 -x - 6)(3x+2)^3
The first term (2x^(2) -3x+1)(4)[(3x+2)^(3)] is expanded to give (8x^2 -12x +4)(3x+2)^3
Then with the same factor of (3x+2)^3 the separate terms can be collected to give the result I obtained.
(20x^2 - 13x - 2) (3x+2)^3
This is found by taking the second term in your question (3x+2)^4(4x-3) and rewriting it as
(3x+2)^3(4x-3)(3x+2) then expanding (4x-3)(3x+2) to get 12x^2 -x - 6
giving (12x^2 -x - 6)(3x+2)^3
The first term (2x^(2) -3x+1)(4)[(3x+2)^(3)] is expanded to give (8x^2 -12x +4)(3x+2)^3
Then with the same factor of (3x+2)^3 the separate terms can be collected to give the result I obtained.
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Please check your typing and update if necessary.....
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228x^5+195x^4-36x^3+16x^2-48x-112