How to solve a system of equations? Help please
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How to solve a system of equations? Help please

[From: ] [author: ] [Date: 11-09-01] [Hit: ]
5y = 203.5y = 14y = 4x = 3 - (4/4)x = 23. Using the first equation and finding y in terms of x:12x + 3y = 363y = 36 - 12xy = (36 - 12x) / 3y = 12 - 4x2x + 4y = 202x + 4*(12 - 4x) = 202x + 48 - 16x = 2048 - 14x = 20-14x = -2814x = 28x = 2y = 12 - 4(2)y = 12 - 8y = 4Use whichever method you find easiest - youll get the same answers either way.-Factor out the GCF 3 in 12x+3y=36Factor out the GCF 2 in 2x+4y=204x+y=12x+2y=10You now have easier numbers to work with.You can plug in now either for x or y, doesnt matter.......

2x + 4y = 20

you can solve for x in terms of y:

2x + 4y = 20
2x = 20 - 4y
x = (20 - 4y) / 2
x = 10 - 2y

and then plug in your new x value back into the OTHER equation and solve for y:

12x + 3y = 36
12(10 - 2y) + 3y = 36
120 - 24y + 3y = 36
120 - 21y = 36
-21y = 36 - 120
-21y = -84
21y = 84
y = 4

Then take y and plug it back in for x:

x = 10 - 2y
x = 10 - 2(4)
x = 10 - 8
x = 2

So your final answers are:

x = 2
y = 4


You could also use this method three other ways:

1. Using the second equation (as above) but finding y in terms of x:

2x + 4y = 20
4y = 20 - 2x
y = (20 - 2x) / 4
y = 5 - (x/2)

12x + 3y = 36
12x + 3*(5 - (x/2)) = 36
12x + 15 - (3/2)x = 36
(21/2)x + 15 = 36
10.5x = 21
x = 2

y = 5 - (2/2)
y = 4


2. Using the first equation and finding x in terms of y:

12x + 3y = 36
12x = 36 - 3y
x = (36 - 3y) / 12
x = 3 - (y/4)

2x + 4y = 20
2*(3 - (y/4)) + 4y = 20
6 - (1/2)y + 4y = 20
6 + 3.5y = 20
3.5y = 14
y = 4

x = 3 - (4/4)
x = 2


3. Using the first equation and finding y in terms of x:

12x + 3y = 36
3y = 36 - 12x
y = (36 - 12x) / 3
y = 12 - 4x

2x + 4y = 20
2x + 4*(12 - 4x) = 20
2x + 48 - 16x = 20
48 - 14x = 20
-14x = -28
14x = 28
x = 2

y = 12 - 4(2)
y = 12 - 8
y = 4

Use whichever method you find easiest - you'll get the same answers either way.

-
Factor out the GCF 3 in 12x+3y=36
Factor out the GCF 2 in 2x+4y=20

4x+y=12
x+2y=10

You now have easier numbers to work with.

You can plug in now either for x or y, doesn't matter.

I'll choose x.

x+2y=10: x=10-2y

4(10-2y)+y=12
40-8y+y=12
-7y=-28
y=4

Plug in y to the second equation
x+2(4)=10
x=2

There you go.
I hope Mike G doesnt thumb me down again, that old troll.
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