1.Compute by using logarithms.
846 ÷ 629 =(the equal sign is supposed to be like this ~ but doubled(=), but I don't know how to do it on the keyboard.)
2. Compute by using logarithms.
4^√6 =
3. Solve by using logarithms and theorems about logarithms. Use e 2.72. Follow the procedure in the examples above.
2^x = 29=
4. Solve by using logarithms and theorems about logarithms. Use e 2.72. Follow the procedure in the examples above. (Round answer to nearest hundredth.)
x = e^4=
thx :)
846 ÷ 629 =(the equal sign is supposed to be like this ~ but doubled(=), but I don't know how to do it on the keyboard.)
2. Compute by using logarithms.
4^√6 =
3. Solve by using logarithms and theorems about logarithms. Use e 2.72. Follow the procedure in the examples above.
2^x = 29=
4. Solve by using logarithms and theorems about logarithms. Use e 2.72. Follow the procedure in the examples above. (Round answer to nearest hundredth.)
x = e^4=
thx :)
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1 . ≈ is ' alt 247 '........find ln 846 - ln 629 = w ..answer is e^w
#2. compute √6 ln 4 = w ...e^w
#3. x ln 2 = ln 29 ...find x
#4. ...nothing to solve...ln x = 4 ---> x = e^4 ≈ ( 2.72)^4
#2. compute √6 ln 4 = w ...e^w
#3. x ln 2 = ln 29 ...find x
#4. ...nothing to solve...ln x = 4 ---> x = e^4 ≈ ( 2.72)^4