Find all points where the tangent line to y= x^3-6x+12 has slope -1
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Find all points where the tangent line to y= x^3-6x+12 has slope -1

[From: ] [author: ] [Date: 11-07-08] [Hit: ]
equate that to -1?? Thanks for any help........
I have no idea where to start...i know the slope of the tangent line is the derivative...so do i take the derivative of the function, equate that to -1?? Thanks for any help..

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That's exactly what you do

y = x^3 - 6x + 12
dy/dx = 3x^2 - 6
dy/dx = -1

-1 = 3x^2 - 6
-1 + 6 = 3x^2
5 = 3x^2
5/3 = x^2
x = +/- sqrt(5/3)
x = +/- (1/3) * sqrt(15)
1
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