SAT question of the day help
[From: ] [author: ] [Date: 11-07-04] [Hit: ]
1623, 24, 25,26EtcSo 5+4+3+2+1+0= 1515/36= 5/12Another way to look at it is this:P(same number)= 6/36which leaves 30/36 differentSo in half of these (15/36)the first number is bigger, and half have the second number bigger.Hoping this helps!......
21, 22, 23, 24, 25, 26
Etc
Now how many have the first number smaller than the second?
12, 13, 14,15, 16
23, 24, 25,26
Etc
So 5+4+3+2+1+0= 15
15/36= 5/12
Another way to look at it is this: P(same number)= 6/36
which leaves 30/36 different
So in half of these (15/36) the first number is bigger, and half have the second number bigger.
Hoping this helps!
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Think about this one.
If you roll a one first time through, the probability is 5/6.
If you roll a 2, the prob is 4/6.
If you roll a 3, the prob is 3/6.
...
If you roll a 6, the prob is 0.
Since these two rolls are indendent add up the products.
(1/6)*(5/6) + (1/6)*(4/6) + (1/6)*(3/6) + (1/6)*(2/6) + (1/6)*(1/6) + (1/6)*(0/6)
= (1/6)*((5+4+3+2+1)/6) = 15/36 = 5/12
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okay, here we go
if you roll 1 on Roll#1, there is a 5/6 chance that it will be less than the second roll.
" 2 on Roll#1, there is a 4/6 chance """"
" 3 on Roll#1, there is a 3/6 chance """"
and so on. if you do the math, i think it should be 5/12. i think.
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There are 36 possible rolls. Of those, 15 have the first higher, 15 have the second higher, and 6 have both rolls the same. So the answer is 15/36 or 5/12.
