3 Algebra Questions(i'll choose best answerer for sure)
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3 Algebra Questions(i'll choose best answerer for sure)

[From: ] [author: ] [Date: 11-06-22] [Hit: ]
like the gigantic ( and ).3. (4x^2y^3)(5x^-3y^-2Z^0)-1.2. since x^-2 = 1/x^2,3.......
*Simplify first 3*
1. (-2)^4 X^3 Y^6
----------------------
(-2)^2 X^-2 Y^-3

2. Pretend that the little paranthesis that i'm going to insert into this problem are one BIG one that cover both of the number. You know..like the gigantic ( and ).
(3X^2)
---------
(5Y^3) and this entire fraction is squared by -2

3. (4x^2 y^3)(5x^-3 y^-2 Z^0)

-
1.
16x^3y^6
---------------
4x^-2y^-3

you can bring the x and y to the top if you change the negative to a positive

16x^3 y^6 x^2 y^3
------------------------
4

=4x^5 y^9


2. since x^-2 = 1/x^2, you can flip the fraction and take it to the power of +2 instead

(5y^3)^2
------------
(3x^3)^2

25y^6
---------
9x^6


3. anything to the power of 0 = 1, so you can ignore that Z term

then just multiply the corresponding constant, x and y

4*5 = 20
x^2 * x^-3 = x^-1 = 1/x
y^3 * y^-2 = y^1 = y

therefore the final answer is:
= 20y/x
1
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