Is it in quadrant 2 or 4? Because one of my books says the answer is 2, but the other one is saying that the restricted domain of arctan can only lay in the first and fourth quadrant.
-
Domain of arc tan is -pi/2 to pi/2, which means 1st and 4th quadrant!
Hence, theta appears in 4th quadrant.
Consider searching in Wikipedia if you ever have this type of problems
Hence, theta appears in 4th quadrant.
Consider searching in Wikipedia if you ever have this type of problems
-
The definition of the function y = arctan(x) the domain is restricted to the interval -pi/2
the positive values are in quadrant 1 and the negative values in quadrant 4.
Then if theta = arctan(-1) then tan(theta) = -1 ... but in that interval the theta is -pi/4 ... quadrant 4.
OK!
Then if theta = arctan(-1) then tan(theta) = -1 ... but in that interval the theta is -pi/4 ... quadrant 4.
OK!
-
i can't remember what the restricted domain is, but i think it can be in both quadrant 2 or 4, since
tan(3pi/4) and tan(7pi/4) both equal -1
tan(3pi/4) and tan(7pi/4) both equal -1