Could you please simplify x^2 - 6x +9 / x^2 -9
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Could you please simplify x^2 - 6x +9 / x^2 -9

[From: ] [author: ] [Date: 11-05-27] [Hit: ]
.then we factorize.now we factorize the bottom part.When you see two squere numbers that are in a rest, you may factirize them.Good Luck!......
thank you

-
x^2 - 6x +9 / x^2 -9

(x - 3)(x - 3) / (x - 3)(x + 3)

(x - 3)/(x + 3)

-
x^2 - 6x + 9
-----------------
x^2 - 9

ok, so you must factorize both up and down part.

In the upper part, we need to find 2 numbers which sum (-6) and multiplies (9)
This are (-3) and (-3)

So...

x^2 - 3x - 3x + 9
------------------------
x^2 - 9

then we factorize.

x(x-3) - 3(x-3)
------------------
x^2 - 9

(x-3) (x-3)
------------
x^2 - 9

now we factorize the bottom part. When you see two squere numbers that are in a rest, you may factirize them.

(x-3)(x-3)
-------------
(x+3)(x-3)

We simplify (x-3)

x-3
-------
x+3


Good Luck!

-
Hi ♥!

Are you a Factor Whiz? If so, factor away:

x² - 6x + 9
-----------------------
x² - 9




(x - 3)(x - 3)
--------------------------
(x - 3)(x + 3)


Cancel out the top-and-bottom pair of (x - 3).


x - 3
---------------
x + 3


Final Answer: (x - 3)/(x + 3)


To check your homework:
http://www.quickmath.com/webMathematica3…
(x^2 - 6x +9)/(x^2 -9)

Hope this helps!

-
First, write the problem correctly............

(x^2 - 6x + 9)/(x^2 - 9) = (x - 3)(x - 3)/(x + 3)(x -3) = (x - 3)/(x + 3)

-
((x - 3)(x - 3))/((x - 3)(x + 3))

(x - 3)/(x + 3)
1
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