thank you
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x^2 - 6x +9 / x^2 -9
(x - 3)(x - 3) / (x - 3)(x + 3)
(x - 3)/(x + 3)
(x - 3)(x - 3) / (x - 3)(x + 3)
(x - 3)/(x + 3)
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x^2 - 6x + 9
-----------------
x^2 - 9
ok, so you must factorize both up and down part.
In the upper part, we need to find 2 numbers which sum (-6) and multiplies (9)
This are (-3) and (-3)
So...
x^2 - 3x - 3x + 9
------------------------
x^2 - 9
then we factorize.
x(x-3) - 3(x-3)
------------------
x^2 - 9
(x-3) (x-3)
------------
x^2 - 9
now we factorize the bottom part. When you see two squere numbers that are in a rest, you may factirize them.
(x-3)(x-3)
-------------
(x+3)(x-3)
We simplify (x-3)
x-3
-------
x+3
Good Luck!
-----------------
x^2 - 9
ok, so you must factorize both up and down part.
In the upper part, we need to find 2 numbers which sum (-6) and multiplies (9)
This are (-3) and (-3)
So...
x^2 - 3x - 3x + 9
------------------------
x^2 - 9
then we factorize.
x(x-3) - 3(x-3)
------------------
x^2 - 9
(x-3) (x-3)
------------
x^2 - 9
now we factorize the bottom part. When you see two squere numbers that are in a rest, you may factirize them.
(x-3)(x-3)
-------------
(x+3)(x-3)
We simplify (x-3)
x-3
-------
x+3
Good Luck!
-
Hi ♥!
Are you a Factor Whiz? If so, factor away:
x² - 6x + 9
-----------------------
x² - 9
(x - 3)(x - 3)
--------------------------
(x - 3)(x + 3)
Cancel out the top-and-bottom pair of (x - 3).
x - 3
---------------
x + 3
Final Answer: (x - 3)/(x + 3)
To check your homework:
http://www.quickmath.com/webMathematica3…
(x^2 - 6x +9)/(x^2 -9)
Hope this helps!
Are you a Factor Whiz? If so, factor away:
x² - 6x + 9
-----------------------
x² - 9
(x - 3)(x - 3)
--------------------------
(x - 3)(x + 3)
Cancel out the top-and-bottom pair of (x - 3).
x - 3
---------------
x + 3
Final Answer: (x - 3)/(x + 3)
To check your homework:
http://www.quickmath.com/webMathematica3…
(x^2 - 6x +9)/(x^2 -9)
Hope this helps!
-
First, write the problem correctly............
(x^2 - 6x + 9)/(x^2 - 9) = (x - 3)(x - 3)/(x + 3)(x -3) = (x - 3)/(x + 3)
(x^2 - 6x + 9)/(x^2 - 9) = (x - 3)(x - 3)/(x + 3)(x -3) = (x - 3)/(x + 3)
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((x - 3)(x - 3))/((x - 3)(x + 3))
(x - 3)/(x + 3)
(x - 3)/(x + 3)