I am lost as to how to get there work-wise. Could someone show me step by step? Thanks!
For a geometic sequence, let a3 = (1/9) and a6 = -3
Find: r, a1
For a geometic sequence, let a3 = (1/9) and a6 = -3
Find: r, a1
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a6/a3 = r^3
-27 = r^3
r = -3
a1 r^2 = a3
a1 = (1/9)/(-3)^2 = 1/81
-27 = r^3
r = -3
a1 r^2 = a3
a1 = (1/9)/(-3)^2 = 1/81