Can someone help with math homework

Solve the following system for x and y.

2x - 8y = 28
4x+ 5y = -7

Let 2x - 8y = 28 be equation 1
and 4x + 5y = -7 be equation 2

Now,by multiplying equation 1 by 2,we get
4x - 16y = 56.Let it be equation 3.

Thereafter,by subtracting equation 2 by equation 3,we get
(4x - 16y) - (4x + 5y) = 56 - (-7)

which simplifies to y = -3.

Further,putting y = -3 in any of the equation 1 or 2,we get x = 2.

Hence,x = 2 and y = -3 is the required solution of the given system of equations.

HoPe YoU uNdErStOoD..... ;)

Solve the first given equation for x:
x = 4y + 14
Substitute this value for x into the second given equation:
4(4y + 14) + 5y = -7
Expand:
16y + 56 + 5y = -7
Combine like terms:
21y = -63
Divide by 21:
y = -3
Substitute this value for y into x = 4y + 14:
x = 4(-3) + 14 = 2

x = 2, y = -3