Help with logarithms
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Help with logarithms

[From: ] [author: ] [Date: 11-05-25] [Hit: ]
......
Could I please have some help to solve this logarithm.

log₅(2x+1) + log₅(x-1) = 1

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Let log be log to base 5

log [ ( 2x + 1 ) ( x - 1 ) ] = 1

2 x ² - x - 1 = 5

2 x ² - x - 6 = 0

( 2x + 3 ) ( x - 2 ) = 0

x = 2 is acceptable

I like your subscript 5.
What annoys me is that I don`t know how to get it ! ! !
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