((1/x)-(1/a))/(x-a)
=(1-(1/a)(x))/(x-a)
=(1- (x/a))/(x-a)
=(a-x)(x-a)
= (-x + a)/ (x - a)
I know the answer is -1/ax, but how do I get there?
=(1-(1/a)(x))/(x-a)
=(1- (x/a))/(x-a)
=(a-x)(x-a)
= (-x + a)/ (x - a)
I know the answer is -1/ax, but how do I get there?
-
= (1/x - 1/a) / (x - a)
= (a/ax - x/ax) / (x - a)
= (a - x) / (ax) / (x - a)
= (a - x) / (ax)(x - a)
= -(x - a) / (ax)(x - a)
= -1/(ax) (Answer)
Have a good day.
= (a/ax - x/ax) / (x - a)
= (a - x) / (ax) / (x - a)
= (a - x) / (ax)(x - a)
= -(x - a) / (ax)(x - a)
= -1/(ax) (Answer)
Have a good day.