Any help would be greatly appreciated...Thanks!
Suppose L = 780 + 2t and C = 12 + 8t represent the population (in thousands) of two cities. In how many years will city L have twice as many inhabitants as city C.
Suppose L = 780 + 2t and C = 12 + 8t represent the population (in thousands) of two cities. In how many years will city L have twice as many inhabitants as city C.
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Assume that t = 0 initially.
The equation asks when L is twice C. So when does L = 2C?
L = 2 C
780 + 2t = 24 + 16t
780 - 14t = 24
756 - 14t = 0
756 = 14t
t = 756 / 14
t = 54 years
The equation asks when L is twice C. So when does L = 2C?
L = 2 C
780 + 2t = 24 + 16t
780 - 14t = 24
756 - 14t = 0
756 = 14t
t = 756 / 14
t = 54 years
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You're looking for L = 2C
780 + 2t = 2*(12 + 8t)
t = 54 years
But that's just Algebra, you don't really need Calculus for this one.
780 + 2t = 2*(12 + 8t)
t = 54 years
But that's just Algebra, you don't really need Calculus for this one.