Algebra 1 math question
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Algebra 1 math question

[From: ] [author: ] [Date: 11-05-06] [Hit: ]
.. and is solved by the equation 175=15+(n-1)5. When I learned this there was something simple I used to do to solve for n and it was super easy. Now I cant find it. I think it had something to do with division.......
175 is the ___th term of 15, 20, 25,30... and is solved by the equation 175=15+(n-1)5. When I learned this there was something simple I used to do to solve for n and it was super easy. Now I can't find it. I think it had something to do with division.

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175 = 15+ (n-1)5

175 = 15 + 5n - 5

175 = 10 + 5n

165 = 5n

165/5 = 5n/5

33 = n

I hope it helps!

EP

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Subtract 15 from both sides of the equation:

175-15=160

Now try to see where (n-1)*5 = 160
First, Divide both sides by 5 to get:

(n-1)=32

then add one to both sides to get n=33.

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first distribute 5 to n and -1... so 175= 15 +5n-5
next combine like terms... 175= 10 + 5n
subtract 10 from 175... 165= 5n
divide by 5 to get n alone... 33=n
so 175 is the 33rd term in the sequence.

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175=15+(n-1)5
175=15+5n-5
175=10+5n
165=5n
n=33
1
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