Operations with Radical Expressions (Algebra 1) problem

This is something I got wrong on my homework- what is 3sqrt(50)+sqrt(8). Evidently it's 17sqrt(2), but that's far off from what I got..

Ok here goes


3sqrt(50)+sqrt(8)

now we can also write as

3sqrt(2x2) + sqrt(4x2)

so sqrt of 25 is 5 and similarly sqrt of 4 is 2

so rewriting

5x3sqrt(2) + 2sqrt(2)
=15sqrt(2) + 2sqrt(2)
=17sqrt(2)

hope this helps..if yes..points plz :-)

I just started my radical expressions this week! Radical expressions, especially dividing them is hard for me. I think I had to answer the same question and got it wrong too. I'll try to solve it.
ALSO I will be using SQ instead of sqrt (it is easier for me to type).
3SQ50+SQ8
3SQ25*2+SQ4*2 (see if the SQs have simpler form, IE 25 = 5*5)
3SQ5*5*2+SQ2*2*2 (If you have two of the same numbers under SQ you can make them whole)
3*5SQ2+2SQ2 (you multiply them when you make them whole, ie 3*5)
15SQ2+2SQ2 (you can add them now since they have the same SQ)
17SQ2

I hope you can understand what I typed, and I hope this helps! Good Luck with you other radical expressions (especially when dividing them).