I am lost can someone help me out.
One number is four more than another.
The product of the numbers is 4 more than the smaller.
Find the two numbers.
One number is four more than another.
The product of the numbers is 4 more than the smaller.
Find the two numbers.
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Smaller number = x
Larger number = x + 4
x(x + 4) = x + 4
x² + 4x = x + 4
x² + 3x - 4 = 0
(x - 1)(x + 4) = 0
x = 1 and x = -4
There are two sets of answers:
Smaller number = x = 1
Larger number = x + 4 = 5
...OR...
Smaller number = x = -4
Larger number = x + 4 = 0
--------------------------------------…
Larger number = x + 4
x(x + 4) = x + 4
x² + 4x = x + 4
x² + 3x - 4 = 0
(x - 1)(x + 4) = 0
x = 1 and x = -4
There are two sets of answers:
Smaller number = x = 1
Larger number = x + 4 = 5
...OR...
Smaller number = x = -4
Larger number = x + 4 = 0
--------------------------------------…
-
You have 2 numbers: x and (x+4)
x(x+4) = x+4
Divide both sides by (x+4)
x = 1
Numbers are 1 and 5
btw, brieanee copied me
x(x+4) = x+4
Divide both sides by (x+4)
x = 1
Numbers are 1 and 5
btw, brieanee copied me
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I am just taking a shot in the dark here. But I ended up with 1 and 5.
Because the difference between 1 and 5 is 4.
And 5*1=5
5 is 4 more than 1, which was your other number.
:-)
Because the difference between 1 and 5 is 4.
And 5*1=5
5 is 4 more than 1, which was your other number.
:-)
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You have 2 numbers: x and (x+4)
x(x+4) = x+4
Divide both sides by (x+4)
x = 1
Numbers are 1 and 5
x(x+4) = x+4
Divide both sides by (x+4)
x = 1
Numbers are 1 and 5
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small number is 1 and the big number is 5, 5x1 = 5, 5-4 is one, the smaller number :)
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n*(n + 4)=4+n
n^2+4n-n-4=0
n^2 + 3n - 4 = 0
(n + 4)*(n - 1) = 0
n = -4 and n = 1
-4 and 0
1 and 5
n^2+4n-n-4=0
n^2 + 3n - 4 = 0
(n + 4)*(n - 1) = 0
n = -4 and n = 1
-4 and 0
1 and 5