I'm solving a quadratic equation by completing the square. It shows you how to do the problem the only thing is one of the steps goes from √(x-1)^2= √3/2 all under the radical to x-1 = √6 /2 the 2 no longer being under a radical. I under stand the x-1 part but why does the √3/2 change to a √6 /2??
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√(3/2) <---Like that right? Because you said it was all under the radical sign?
What they did was Rationalize the Denominator.
√(3/2) = √3/√2
To rationalize the denominator, they multiplied the numerator and denominator by √2
√3/√2 * √2/√2 = √6/√4 = √6/2
What they did was Rationalize the Denominator.
√(3/2) = √3/√2
To rationalize the denominator, they multiplied the numerator and denominator by √2
√3/√2 * √2/√2 = √6/√4 = √6/2
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√(3/2)
= √(6/4)
= √(6) / 2
= √(6/4)
= √(6) / 2