a company sells recordable CD'S for 80 cents each and play-only CD'S for 60 cents. the company recieves $76 for an order of 100 CD'S : however, the customer neglected to specify how many of each type to send. determine the number of each type of CD's the should be sent.
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Let:
x = # of recordable CD's
y = # of play-only CD's
Here:
.8x + .6y = 76.00
x + y = 100
We can multiply the first function by 10 to get:
8x + 6y = 760
x + y = 100
Then, by elimination method:
8x + 6y = 760
-6(x + y = 100)
8x + 6y = 760
-6x - 6y = -600
2x = 160
x = 80
Finally, substitute that x value for either equation and solve for y.
80 + y = 100
y = 100 - 80
y = 20
Therefore, 80 recordable CD's and 20 play-only CD's should be sent to achieve $76 and 100 CD's.
I hope this helps!
x = # of recordable CD's
y = # of play-only CD's
Here:
.8x + .6y = 76.00
x + y = 100
We can multiply the first function by 10 to get:
8x + 6y = 760
x + y = 100
Then, by elimination method:
8x + 6y = 760
-6(x + y = 100)
8x + 6y = 760
-6x - 6y = -600
2x = 160
x = 80
Finally, substitute that x value for either equation and solve for y.
80 + y = 100
y = 100 - 80
y = 20
Therefore, 80 recordable CD's and 20 play-only CD's should be sent to achieve $76 and 100 CD's.
I hope this helps!