f(x) = { x+π, x∈[-π, 0]
{ -x+π, x∈(0, π)
This is a piecewise function, and i'm aware that it is a even function, however I do not know why it is,
I tried say x = π/2, hence
f(x=π/2) = 3π/2, x∈[-π, 0]
π/2, x∈(0, π)
f(-x=-π/2) = π/2, x∈[-π, 0]
3π/2, x∈(0, π)
Here does f(x) = f(-x), i don't see how it does since the range which each value lie in is different. But i am informed that it is an even function.
Any help would be gratefull. Thank you.
{ -x+π, x∈(0, π)
This is a piecewise function, and i'm aware that it is a even function, however I do not know why it is,
I tried say x = π/2, hence
f(x=π/2) = 3π/2, x∈[-π, 0]
π/2, x∈(0, π)
f(-x=-π/2) = π/2, x∈[-π, 0]
3π/2, x∈(0, π)
Here does f(x) = f(-x), i don't see how it does since the range which each value lie in is different. But i am informed that it is an even function.
Any help would be gratefull. Thank you.
-
Try graphing the functions.
Once this is graphed, an even function will be symmetric about the y-axis.
Once this is graphed, an even function will be symmetric about the y-axis.