Even or odd functions
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Even or odd functions

[From: ] [author: ] [Date: 11-04-23] [Hit: ]
however I do not know why it is,I tried say x = π/2,f(x=π/2) = 3π/2,x∈[-π, 0] π/2, x∈(0,......
f(x) = { x+π, x∈[-π, 0]
{ -x+π, x∈(0, π)

This is a piecewise function, and i'm aware that it is a even function, however I do not know why it is,

I tried say x = π/2, hence

f(x=π/2) = 3π/2, x∈[-π, 0]
π/2, x∈(0, π)

f(-x=-π/2) = π/2, x∈[-π, 0]
3π/2, x∈(0, π)

Here does f(x) = f(-x), i don't see how it does since the range which each value lie in is different. But i am informed that it is an even function.

Any help would be gratefull. Thank you.

-
Try graphing the functions.

Once this is graphed, an even function will be symmetric about the y-axis.
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