I'm not sure what to do when simplifying this, so working out would be good
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Lets rewrite it so that it doesn't look as confusing.
3(x + 2)²(x - 5)² + 2(x + 2)(x - 5)³
Since there are multiple (x + 2) and (x- 5)'s out there, we can pull those out.
They both have in common 1 set of x +2 and 2 sets ofx - 5.
= (x + 2)(x - 5)²[ 3(x + 2) + 2(x - 5) ]
= (x + 2)(x - 5)²[ 3x + 6 + 2x - 10 ]
= (x + 2)(x - 5)²(5x - 4)
Hope this helps :D
3(x + 2)²(x - 5)² + 2(x + 2)(x - 5)³
Since there are multiple (x + 2) and (x- 5)'s out there, we can pull those out.
They both have in common 1 set of x +2 and 2 sets ofx - 5.
= (x + 2)(x - 5)²[ 3(x + 2) + 2(x - 5) ]
= (x + 2)(x - 5)²[ 3x + 6 + 2x - 10 ]
= (x + 2)(x - 5)²(5x - 4)
Hope this helps :D
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(x + 2)^2 3 (x - 5)^2 + (x - 5)^3 2 (x + 2)
just expand the formulas of (a+b)^2 and (a+b)^3
then simplify it you will get this answer
-200 + 230 x + 57 x^2 - 44 x^3 + 5 x^4
just expand the formulas of (a+b)^2 and (a+b)^3
then simplify it you will get this answer
-200 + 230 x + 57 x^2 - 44 x^3 + 5 x^4
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(x+2)^2 3(x-5)^2 + (x-5)^3 2(x+2) = (x+2) (x-5)^2 [3(x+2)+ 2(x-5)] (Commonly take outside (x+2)(x-5)^2
= (x+2) (x-5)^2 [3x+6+ 2x-10] (simplification)
= (x+2)(x-5)^2[5x - 4}
= (x+2) (x-5)^2 [3x+6+ 2x-10] (simplification)
= (x+2)(x-5)^2[5x - 4}
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(x^2 + 4x +4) + 3(x^2-10x+25) + x^3-15x-125 + 2x+4
(x^2 + 4x +4) + (3x^2 - 30x + 75) + x^3 - 13x - 121
4x^2 -26x +79 + x^3 - 13x - 121
x^3 + 4x^2 - 39x - 42
I think.
(x^2 + 4x +4) + (3x^2 - 30x + 75) + x^3 - 13x - 121
4x^2 -26x +79 + x^3 - 13x - 121
x^3 + 4x^2 - 39x - 42
I think.
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5(x-5)^4 + 56(x-5)^3 + 147 (x-5)^2
(x-5)^2 (5x^2+6x-8)
(x-5)^2 (x+2) (5x-4)
x=5, -2, 4/5
(x-5)^2 (5x^2+6x-8)
(x-5)^2 (x+2) (5x-4)
x=5, -2, 4/5
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the answer is 3