Let f(z) be entire and let |f(z)| ≥ 1 on the whole complex plane. Prove that f
is constant
is constant
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Just consider 1 / f(z), and use Liouville's theorem.
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"I tried Liouville's thereom but that only applies when f(z) <= M"
Hrmmm? That's why you need to consider 1 / f(z) instead of f(z)...
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"I tried Liouville's thereom but that only applies when f(z) <= M"
Hrmmm? That's why you need to consider 1 / f(z) instead of f(z)...