2 + 3log2(3x-1)=17
3log2(3x-1)=15
log2(3x-1)=5
Can anyone explain to me what to do after this step? The answer is 11, but I'm unsure of how to get there. Any help would be great!
3log2(3x-1)=15
log2(3x-1)=5
Can anyone explain to me what to do after this step? The answer is 11, but I'm unsure of how to get there. Any help would be great!
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Let log be log to base 2
2 + 3 log ( 3x - 1 ) = 17
3 log ( 3x - 1 ) = 15
log ( 3x - 1 ) = 5
3x - 1 = 2^5
3x = 33
x = 11
2 + 3 log ( 3x - 1 ) = 17
3 log ( 3x - 1 ) = 15
log ( 3x - 1 ) = 5
3x - 1 = 2^5
3x = 33
x = 11
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Good to hear---pleased to help.
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