quadratic equation. I need to factor by grouping
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You have :
--------------------------------------…
B = 3 x*2 + 5 x - 2
B = ( 3x - 1 ) ( x + 2 ) <---------------------------------------…
Chosen from :
B = ( 3x + 1 ) ( x - 2 ) ... 3x^2 -5x - 2
B = ( 3x -1 ) ( x +2 ) ....... 3x^2 + 5x - 2 <------------------------------
B = ( 3x +2 ) ( x - 1 ) ---- 3x^2 - x - 2
B = ( 3x - 2 ) ( x +1 ) ---- 3 x^2 + x - 2
--------------------------------------…
B = 3 x*2 + 5 x - 2
B = ( 3x - 1 ) ( x + 2 ) <---------------------------------------…
Chosen from :
B = ( 3x + 1 ) ( x - 2 ) ... 3x^2 -5x - 2
B = ( 3x -1 ) ( x +2 ) ....... 3x^2 + 5x - 2 <------------------------------
B = ( 3x +2 ) ( x - 1 ) ---- 3x^2 - x - 2
B = ( 3x - 2 ) ( x +1 ) ---- 3 x^2 + x - 2
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factorised: (3x+1)(x-2)
Therefore x=2 and x=0.33333 = one third
Hope this helps, wasn't sure what you meant by "grouping" but this is what I would do.
Therefore x=2 and x=0.33333 = one third
Hope this helps, wasn't sure what you meant by "grouping" but this is what I would do.
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3x^2 +5x - 2 = (3x - 1)(x +2)
x = -2, 1/3
..
x = -2, 1/3
..
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3x^2+5x-2
x(3x + 5) = 2
1. x = 2
2. 3x = -5
x = -5/3
x(3x + 5) = 2
1. x = 2
2. 3x = -5
x = -5/3
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it's expression
=(3x-1)(x+2)
=(3x-1)(x+2)