I'm a sophomore in high school and I just CAN'T pass it! I've always hated Math I'm good at Multiplying etc basic stuff but I just don't get it. I don't understand one thing when the teacher explains it and last year I had a overall 0.4 GPA (I never did homework failed all my tests) well now I do homework but I still fail tests but I got a 3.0 last progress report and have a 2.4 atm. I did ALL my homework in my Alg 1 class this semester but I still had an F and just gave up and am not bothering doing the hw in his class because I have a 30% and there is no hope lol. I do all my hw in classes but I still struggle with tests/quizzes (but I still can pass) Well now they have a online Algebra 1 make up type thing and I've been procrastinating on it and have 60 items due or else I get dropped but I was doing the work and don't understand any of it...what to do!!
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What you do to one side, YOU MUST DO TO THE OTHER!!!!!!
That, my friend, is a cardinal rule for math. Learn that, and you'll at least get a D+.
For example, a typical algebra one problem is something like 2x^2 = 4
How do we solve for x? Simple. What we first want to do is get all like terms on one side, by like terms I mean get all x's one one side and all number without x's or y's on the other. So with this problem, we do this:
x^2 = 4/2
Which equals x^2 = 2
We're almost done here, we just have on thing left to do. We want to solve the equation for x, NOT x^2. How do we solve for x? We simply take the square root of both sides. Taking the square root effectively cancels out any number or variable raised to the second power. This is because of the fact that the square root root of a number is EXACTLY the same as raising a number to the ^1/2 (one half) power. so when you raise (x^2)^1/2 power, you're essentially multiplying 2 by 1/2 which equals 1. Since we raised x^2 to the 1/2 power, WE MUST raise 2 to the one half power as well. Do so will give us: x = √2 AND -√2. Whenever you take the square root of a number, you will get two answers, a positive answer and a negative answer. So the final answer for our problem, what is x= to when we have the equation: 2x^2 = 4, is x = √ 2 and x= -√2.
That, my friend, is a cardinal rule for math. Learn that, and you'll at least get a D+.
For example, a typical algebra one problem is something like 2x^2 = 4
How do we solve for x? Simple. What we first want to do is get all like terms on one side, by like terms I mean get all x's one one side and all number without x's or y's on the other. So with this problem, we do this:
x^2 = 4/2
Which equals x^2 = 2
We're almost done here, we just have on thing left to do. We want to solve the equation for x, NOT x^2. How do we solve for x? We simply take the square root of both sides. Taking the square root effectively cancels out any number or variable raised to the second power. This is because of the fact that the square root root of a number is EXACTLY the same as raising a number to the ^1/2 (one half) power. so when you raise (x^2)^1/2 power, you're essentially multiplying 2 by 1/2 which equals 1. Since we raised x^2 to the 1/2 power, WE MUST raise 2 to the one half power as well. Do so will give us: x = √2 AND -√2. Whenever you take the square root of a number, you will get two answers, a positive answer and a negative answer. So the final answer for our problem, what is x= to when we have the equation: 2x^2 = 4, is x = √ 2 and x= -√2.
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