Explain distance formula perimeter
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Explain distance formula perimeter

[From: ] [author: ] [Date: 12-03-10] [Hit: ]
EF, and FD.There is a cheat cheat in our math textbook because we have the whole entire thing on our school computers, but I use it to check my work.I have been getting the perimeter as 12.1 units but the answer key says 36.......
Basically we have this one problem on homework where it goes "Find the perimeter of the figure" and the coordinates are F=(8,4) D=(5,1) and E= (6,6) So how do I work this problem out? I tried twice to find the distance between all by using the distance formula for lines DE, EF, and FD. There is a cheat cheat in our math textbook because we have the whole entire thing on our school computers, but I use it to check my work. I have been getting the perimeter as 12.1 units but the answer key says 36.2 units? How am I to work the problem out? I use D=(X(2)-X(1))Squared + (Y(2)-Y(1))Squared and then D=the square root of the answer. Its a bit confusing because I cannot use the special characters in answers, but I hope you know what I mean. Anyway, please explain what I am doing wrong?
My answers were
Line FD=4.2 (nearest tenth)
Line DE=5.2 (Nearest tenth)
Line EF= 2.8 (Nearest tenth)
and added up I get perimeter=12.2
Thanks in advanced

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I'd say that the answer key is wrong. You're calculating the lengths correctly.

The distance FD is the square root of the sum of the squares of the x and y differences:

Side FD:

x change = 3 (from 8 to 5)

y change = 3 (from 4 to 1)

distance = sqrt(3^2 + 3^2) = sqrt(9 + 9) = sqrt(18) = 4.2
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